So anyway I put my name on a list last year saying I could help out with math. Someone has finally sent me an email asking for help. The Thins is, they just asked a question I don't know how to do. I know algebra and calculus fairly well, but not this:
If you have 30 buses, 12 with blue, 8 with red, and 5 with both, how many have no color?I figure that some of you have had awesome foreign math classes in preschool, while my pathetic American math sucked. If you come up with an answer, tell me, and how you did it, so I can help this person with their remedial math.
Erm.. Dude. Why is that hard?
30 buses are quite a lot.
Well.. uh, 12+8+5 = 25, which leaves us with 5 without color.But that's too simple, eh?I made you a little diagram. I hope it helps…
Is that 9 in the blue circle a mistake? If you have 12 blue buses with blue, and 5 of those have red, then 12 minus 5 is 7 isn't it?
If you need to have a tutor, I'll help. I'm great with math. One of the best in the state.
Seeing as it's virtually impossible to have a bus lacking any color whatsoever and as that you simply implied the remainder has no color then I'll say none.
I don't need a tutor, I AM the tutor. I can calc II like it's nothing, but this confused me. But I came up with 15 colorless buses.
Black is every color, white is no color =D
that's kinda awkward of a problem… =/There are 5 colourless.
You see 30 buses.on the right there are 12 red buses. In the middle you see 8 blue buses. on the left there are 5 wich are coloured red and blue. so you see:12 buses + 8 buses + 5 buses = 25 buses. So there are 5 left. Whats so hard. @Austin. How can the buses with both colours be part of the buses with red or blue? That makes no sense!@MrPacman srry but it's the other way around. Ever tried to get a rainbow out of black light.And yeah, call me a smartass if you want.