What if I…put it in parser friendly format?

int main ( int argc , char * argv [ ] ) {

std::ofstream fw ( "" ) ;

std::ifstream fr ( "" , std::ios::ate ) ; int flen = fr.tellg ( ) ; fr.seekg ( 0 , std::ios::beg ) ;

char * data = new char [ flen ] ;

v = 0 ; while ( ( fr.good ( ) ) ) data [ v ++ ] = fr.get ( ) ;

data [ v - 1 ] = 0 ;

int para = 0 , brac = 0 , quot = 0 ;

v = 0 ; while ( ( data [ ++ v ] != 0 ) ) {

if ( ( data [ v ] == ( ( char ) 039 ) || data [ v ] == ( ( char ) 034 ) ) && data [ v - 1 ] != ( ( char ) 092 ) ) quot =! quot ;

if ( quot == 0 ) {

brac += ( data [ v ] == ( ( char ) 123 ) ) - ( data [ v ] == ( ( char ) 125 ) ) ;

para += ( data [ v ] == ( ( char ) 040 ) ) - ( data [ v ] == ( ( char ) 041 ) ) ; }

if ( data [ v ] == ( ( char ) 092 ) n && brac == 0 && para == 0 && data [ v - 1 ] != ( ( char ) 059 ) ) fw << "" ;

fw << data [ v ] ; }

fw.close ( ) ; fr.close ( ) ;

system ( "" ) ;

return 0 ; }

out.txt
in.txt
;
start out.txt

int main(int argc,char *argv[]){

std::ofstream fw("")

std::ifstream fr("",std::ios::ate);int flen=fr.tellg();fr.seekg(0,std::ios::beg)

char *data=new char[flen]

v=0;while(fr.good()):data[v++]=fr.get()

data[v-1]=0

int para=0,brac=0,quot=0

v=0;while(data[++v]!=0):

. if((data[v]==''||data[v]=='")&&data[v-1]!='\) quot=!quot

. if quot==0:

. . brac+=(data[v]=='{)-(data[v]=='})

. . para+=(data[v]=='()-(data[v]=='))

. if(data[v]=='\n&&brac==0&&para==0&&data[v-1]!=';) fw<<""

. fw<<data[v]

fw.close();fr.close()

system("")

return 0;}

I decided to be destructive and work on the input data before transfering/converting it to the code data

Also, the greatness of space based tokenization has allowed for !! to be complete

resyntaxers just take somebody elses hard work and make it prettier.

Resyntaxers are thieves!!